回復 48# mathca 的帖子
\(\frac{{{\sin }^{2}}x}{{{2}^{2n}}{{\sin }^{2}}\frac{x}{{{2}^{n}}}}=\frac{{{\sin }^{2}}x}{{{x}^{2}}}\times \frac{{{x}^{2}}}{{{2}^{2n}}{{\sin }^{2}}\frac{x}{{{2}^{n}}}}=\frac{{{\sin }^{2}}x}{{{x}^{2}}}\times \sin {{\left( \frac{\frac{x}{{{2}^{n}}}}{\sin \frac{x}{{{2}^{n}}}} \right)}^{2}}\)