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101嘉義高中(代理)

回復 22# leo790124 的帖子

用孟氏定理可算出
AR:DR = EP:BP = CQ:FQ = 2:3

△AFR:△ABD = (1 * 2):(4 * 5) = 1:10
△AFR:△ABC = 1:20

△BDP:△BCE = (1 * 3):(2 * 5) = 3:10
△BDP:△ABC = 1:10

△CEQ:△ACF = (1 * 2):(3 * 5) = 2:15
△CEQ:△ABC = 1:30

△PQR = △ABC - (△ABD + △BCE + △ACF) + (△AFR + △BDP + △CEQ)
△PQR:△ABC = 1:10

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