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113新北市高中聯招

回覆 9# Superconan 的帖子

令所求=x+y+z

a=(x-y+z)/2
b=(x+y-z)/2
c=(-x+y+z)/2
等號成立時
x=36/11,y=4/11,z=9/11
=>c=-23/22

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回覆 23# ingibitor0606 的帖子

9.
E=(1+E)/2+(2+E)/4+(3+E)/8+3/8
=>E=14
10.
(p^2+(1-p^2))(q^2+(1-q^2))>=所求^2
=>1>=所求^2

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