請教第2題 算了好幾次都是\(\displaystyle \frac{\sqrt{2+\sqrt{2}}}{4}\)
不知道問題出在哪
以下為算式過程
以\(\vec{OA},\vec{OB}\)張出的三角形面積為\(\displaystyle \frac{1}{2}\times \sqrt{2}\times\sqrt{3}\times \frac{1}{\sqrt{2}}=\frac{\sqrt{3}}{2}\)
高為\(\displaystyle \sqrt{3}\cdot \frac{\sqrt{2+\sqrt{2}}}{2}\)
所求體積為\(\displaystyle \frac{\sqrt{3}}{2}\times \sqrt{3}\cdot \frac{\sqrt{2+\sqrt{2}}}{2}\times\frac{1}{3}=\frac{\sqrt{2+\sqrt{2}}}{4}\)