回復 1# BambooLotus 的帖子
\(\displaystyle\begin{align}
& a=\sqrt[3]{x-3},b=\sqrt[3]{5x-6},c=\sqrt[3]{2x-4},d=\sqrt[3]{4x-5} \\
& a+b=c+d \\
& {{a}^{3}}+{{b}^{3}}={{c}^{3}}+{{d}^{3}} \\
& \\
& {{\left( a+b \right)}^{3}}={{\left( c+d \right)}^{3}} \\
& {{a}^{3}}+{{b}^{3}}+3ab\left( a+b \right)={{c}^{3}}+{{d}^{3}}+3cd\left( c+d \right) \\
& ab\left( a+b \right)=cd\left( c+d \right) \\
& \\
& \left( 1 \right)\ a+b=c+d=0,x=\frac{3}{2} \\
& \left( 2 \right)\ ab=cd,x=1\ or\ \frac{2}{3} \\
\end{align}\)
