回復 1# thankyou 的帖子
\(\begin{align}
& {{3}^{x}}-\frac{2(a-1)}{{{3}^{x}}}=a-3 \\
& {{\left( {{3}^{x}} \right)}^{2}}-\left( a-3 \right){{3}^{x}}=2\left( a-1 \right) \\
& {{\left( {{3}^{x}}-\frac{a-3}{2} \right)}^{2}}={{\left( \frac{a+1}{2} \right)}^{2}} \\
& {{3}^{x}}=a-1 \\
& \\
& a>1 \\
\end{align}\)
