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回復 1# panda.xiong 的帖子

\(\frac{1}{6}+\frac{5}{6}\times \frac{1}{6}+{{\left( \frac{5}{6} \right)}^{2}}\times \frac{1}{6}+{{\left( \frac{5}{6} \right)}^{3}}\times \frac{1}{6}+\cdots +{{\left( \frac{5}{6} \right)}^{n-1}}\times \frac{1}{6}>0.9\)

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