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回復 1# thankyou 的帖子

\(\begin{align}
  & \Delta ABC=\frac{1}{2}\times \overline{AC}\times \overline{BC} \\
& \Delta ABC=\Delta AOC+\Delta BOC \\
& =\frac{1}{2}\times \overline{OC}\times \overline{OA}\times \sin \angle AOC+\frac{1}{2}\times \overline{OC}\times \overline{OB}\times \sin \angle BOC \\
& =\frac{1}{2}\times \overline{OC}\times \overline{OC}\times \sin \angle AOC+\frac{1}{2}\times \overline{OC}\times \overline{OC}\times \sin \angle AOC \\
& ={{\overline{OC}}^{2}}\times \sin \angle AOC \\
&  \\
& \sin \angle AOC=\frac{1}{2} \\
& \angle AOC={{30}^{{}^\circ }}\ or\ {{150}^{{}^\circ }} \\
& \angle CAB={{15}^{{}^\circ }}\ or\ {{75}^{{}^\circ }} \\
\end{align}\)

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回復 3# thankyou 的帖子

跟上面差不多
作\(\overline{CD}\)垂直\(\overline{AB}\)於D,注意:D可能在\(\overline{OA}\)或\(\overline{OB}\)上
\(\begin{align}
  & \Delta ABC=\frac{1}{2}\times \overline{AC}\times \overline{BC} \\
& \Delta ABC=\Delta AOC+\Delta BOC \\
& =\frac{1}{2}\times \overline{OA}\times \overline{CD}+\frac{1}{2}\times \overline{OB}\times \overline{CD} \\
& =\frac{1}{2}\times \overline{OC}\times \overline{CD}+\frac{1}{2}\times \overline{OC}\times \overline{CD} \\
& =\overline{OC}\times \overline{CD} \\
&  \\
& \overline{CD}=\frac{1}{2}\overline{OC} \\
& \angle COD={{30}^{{}^\circ }} \\
& \angle CAB={{15}^{{}^\circ }}\ or\ {{75}^{{}^\circ }} \\
\end{align}\)

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