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1副撲克遺失1張 由剩下51張取兩張試問:兩張皆為黑桃的機率

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\(\begin{align}
  & \left( 1 \right)\quad \frac{1}{4}\times \frac{C_{2}^{12}}{C_{2}^{51}}+\frac{3}{4}\times \frac{C_{2}^{13}}{C_{2}^{51}} \\
&  \\
& \left( 2 \right)\quad \frac{\frac{3}{4}\times \frac{C_{2}^{13}}{C_{2}^{51}}}{\frac{1}{4}\times \frac{C_{2}^{12}}{C_{2}^{51}}+\frac{3}{4}\times \frac{C_{2}^{13}}{C_{2}^{51}}} \\
\end{align}\)

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