回復 10# steve38 的帖子
計算第2題
\(\begin{align}
& \left( {{x}^{2}}+x+1 \right)\left( 1+x+{{x}^{2}}+\cdots +{{x}^{9}}+{{x}^{10}} \right)={{\left( 1+x+{{x}^{2}}+\cdots +{{x}^{6}} \right)}^{2}} \\
& x\ne 1 \\
& \frac{{{x}^{3}}-1}{x-1}\times \frac{{{x}^{11}}-1}{x-1}={{\left( \frac{{{x}^{7}}-1}{x-1} \right)}^{2}} \\
& \left( {{x}^{3}}-1 \right)\left( {{x}^{11}}-1 \right)={{\left( {{x}^{7}}-1 \right)}^{2}} \\
& {{x}^{11}}-2{{x}^{7}}+{{x}^{3}}=0 \\
& {{x}^{3}}{{\left( {{x}^{4}}-1 \right)}^{2}}=0 \\
& x=0\ or\ -1 \\
\end{align}\)