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回復 1# shmilyho 的帖子

y x = a*cos4x + b*sin4x , 等式兩邊對x微分得:
y' x + y = - 4a*sin4x + 4b*cos4x , 再微分得:
y'' x + 2y' = - 16a*cos4x - 16b*sin4x = -16xy , 得證.

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