回覆 11# lisa2lisa02 的帖子
計算第 3 題
AB^2 = 1^2 + 1^2 - 2 * 1 * 1 * cos∠AOB
BC^2 = 1^2 + 1^2 - 2 * 1 * 1 * cos∠BOC
CA^2 = 1^2 + 1^2 - 2 * 1 * 1 * cos∠COA
AB^2 + BC^2 + CA^2 = 6 - 2(cos∠AOB + cos∠BOC + cos∠COA)
cos∠AOB + cos∠BOC + cos∠COA = -1
cos∠AOB + cos∠BOC + cos(∠AOB + ∠BOC) = -1
∠AOB + ∠BOC = π
∠ABC = π/2