回覆 11# zj0209 的帖子
第 11 題
x < 0,f(x / (x - 1)) = xf(x)
x = -1,f(1/2) = -f(-1) = f(1) = 1
x = -1/2,f(1/3) = (-1/2)f(-1/2) = (1/2)f(1/2) = 1/2!
x = -1/3,f(1/4) = … = 1/3!
:
:
f(1/k) = 1/(k - 1)!
所求 = 1/99! + 1/98! + 1/2! * 1/97! + … + 1/49! * 1/50!
= (1/99!) * {[C(99,0) + C(99,99)] / 2 + [C(99,1) + C(99,98)] / 2 + … + [C(99,49) + C(99,50)] / 2}
= 2^98 / 99!