回覆 1# ChengWeik 的帖子
x = √3 + √2，y = √3 - √2
x^2024 + y^2024 是整數
x + y = 2√3，xy = 1
x^2 + y^2 = 10
x^4 + y^4 = 10^2 - 2 ≡ 8 (mod 10)
x^8 + y^8 ≡ 8^2 - 2 ≡ 2 (mod 10)
x^16 + y^16 ≡ 2^2 - 2 ≡ 2 (mod 10)
:
:
x^2024 + y^2024 ≡ 2 (mod 10)
y^2024 趨近於 0
a = 1，b = 9
