回復 1# anson721 的帖子
令\(a=2\sqrt{{{x}^{2}}-121},b=11\sqrt{{{x}^{2}}-4}\)
\(\begin{align}
& a+b=\sqrt{147}x \\
& {{b}^{2}}-{{a}^{2}}=\left( b+a \right)\left( b-a \right)=121\left( {{x}^{2}}-4 \right)-4\left( {{x}^{2}}-121 \right)=117{{x}^{2}} \\
& b-a=\frac{117}{147}\sqrt{147}x \\
& a=\frac{15}{147}\sqrt{147}x \\
& \\
& 2\sqrt{{{x}^{2}}-121}=\frac{15}{147}\sqrt{147}x \\
& x=14 \\
\end{align}\)
