回復 1# rueichi 的帖子
\(\begin{align}
& \frac{n}{\left( n+15 \right)\left( n+14 \right)\left( n+13 \right)}>\frac{n-1}{\left( n+14 \right)\left( n+13 \right)\left( n+12 \right)} \\
& \frac{n}{\left( n+15 \right)\left( n+14 \right)\left( n+13 \right)}>\frac{n+1}{\left( n+16 \right)\left( n+15 \right)\left( n+14 \right)} \\
& n=7 \\
\end{align}\)