回復 1# P78961118 的帖子
\(\begin{align}
& \overline{CE}=x,\overline{AF}=4x,\overline{DE}=y,\overline{EF}=3y \\
& \overline{BF}=4\sqrt{3}x,\overline{BE}=4\sqrt{3}x-3y \\
& \frac{x}{4\sqrt{3}x-3y}=\tan 15{}^\circ =2-\sqrt{3} \\
& \frac{x}{y}=\frac{9\sqrt{3}+6}{23} \\
\end{align}\)
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2017-10-20 22:31
