微積分有關極限的證明
Without using any negative words, state what it means to say that the limit of f(x), as x approaches a, is not L.回復 1# Amis 的帖子
\(\exists \epsilon>0\) s.t. \(\forall \delta>0, \exists x\) (depends on \(\delta)\) with \(0<\left|x -a \right|<\delta\) and \(\left|f\left(x\right) -L \right|\geq\epsilon\).回復 2# weiye 的帖子
我一開始也是這樣寫，只是不太確定！現在我懂了～感謝～～
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