## Math Pro 數學補給站's Archiver

### 微積分有關極限的證明

Without using any negative words, state what it means to say that the limit of f(x), as x approaches a, is not L.

### 回復 1# Amis 的帖子

$$\exists \epsilon>0$$ s.t. $$\forall \delta>0, \exists x$$ (depends on $$\delta)$$ with $$0<\left|x -a \right|<\delta$$ and $$\left|f\left(x\right) -L \right|\geq\epsilon$$.